what is the value of log (1+x) if |x|<1
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According to the rules of logarithm we know that log 1000= 3. As we by deafult have 10 in the base accordingly to the main rule. We get 10³= 1000. Therefore,
log x= -1
x^ -1 =10
1/x=10
X= 1/10
But accordin to calculus we have ‘e' by deafult in the base. Therefore,
log x=-1
X^-1 = e
1/ x= e
X= 1/e
joelimman60:
you are so beutiful
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