what is the value of log (1+x) if |x|<1 .
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So the answer is 1/10. If log x = -1, then x = 0.1 (Common logarithms) and x = e^-1 in case of natural logarithms. You to mention the base of the logarithm. If the base is e then the value of x will be 1/e or e^-1 where e is exponential whose value is 2.73.
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