what is the value of log e?
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the value of log e is 2.7
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We know that loga(m) = x, then a^x = m.
So…this answer totally depends on the value of a i.e. the base of the logarithm.
If base taken is 10 -
log10(e) = log e = log (2.7182818) = 0.434294482
(Value of e= 2.7182818 approx.)
If base taken is e itself -
ln(e) = loge(e) = 1.
As if the log of a numver is to be taken out and the base is same as the number itself, then the log is always equal to 1. ( put values of a and m in a^x = m and check for yourself)
So…this answer totally depends on the value of a i.e. the base of the logarithm.
If base taken is 10 -
log10(e) = log e = log (2.7182818) = 0.434294482
(Value of e= 2.7182818 approx.)
If base taken is e itself -
ln(e) = loge(e) = 1.
As if the log of a numver is to be taken out and the base is same as the number itself, then the log is always equal to 1. ( put values of a and m in a^x = m and check for yourself)
Pranothi1:
Please add this as the brainliest ans
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