Math, asked by govinda4119, 1 year ago

What is the value of log(e(e(e.....)^1/2)^1/2)^1/2)?

Answers

Answered by KarupsK
6

 log( \sqrt{e \sqrt{e \sqrt{e \sqrt{e \sqrt{e......} } } } } )
take
y =  \sqrt{e \sqrt{e \sqrt{e \sqrt{e \sqrt{e.....} } } } }
then
y =  \sqrt{ey}
 {y}^{2}  = ey
y = e
 log(e)
1
Answered by Anonymous
2

Step-by-step explanation:

 \sf \: log( \sqrt{e \sqrt{e \sqrt{e \sqrt{e \sqrt{e......} } } } } ) \\

take

 \sf \: y = \sqrt{e \sqrt{e \sqrt{e \sqrt{e \sqrt{e.....} } } } } \\  \\ </p><p>

then

 \sf \: y = \sqrt{ey}</p><p>   \\ </p><p> \sf \: {y}^{2} = e</p><p>

Similar questions