what is the value of log10(17.5)?
given that,log10(5)=0.6990 and log10(7)=0.8451
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1.2430 is the correct answer but in amcat it will be 1.2431
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Answer:
given that,
log10(5)=0.6990 and log10(7)=0.8451
log10(17.5)
Can be written as
log10(25*0.7)
Log(m*n) =logm +logn
log10(25*0.7)=log10(25) +log(0.7)
=log10(5^2) + log(7/10)
Log(m^n) =nlogm
Log (m/n)= logm -logn
=log10(5^2) + log(7/10)
=2log10(5) + log(7) -log(10)
=2(0.6990) + 0.8451 - 1
=1.398+ 0.8451 - 1
=1.2431
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