What is the value of log2205?vgiven that log 5=a,log 7=b and log3=c
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→log 2205
= log( 441×5)
=log(3×3×5×7×7)
=log(3² × 5×7²)
= log 3² + log 5 +log 7² → [As log ABC = log A +log B +log C and log A²= 2 log A]
= 2 log 3 + log 5 + 2 log 7
= 2 c + a + 2 b → [∵ log 5=a,log 7=b and log 3=c]
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