Question

What is the value of m after executing the following code?
int n = 123456789;
int m = 0;
while (n != 0)
{
m = (10 * m) + (n % 10);
n = n / 10;

Answer 1

Answer:

mn 10 nn 10 - Course Hero

int n = 123456789; int m = 0; while (n != 0) { m = (10 * m) + (n % 10); n = n / 10; } a. 0, 123456789 b. 987654321, 123456789 c. 987654321, 0 d. None of the above

Answer 2

Question:-

Find the value of m after execution of the following code

Code:-

int n = 123456789;

int m = 0;

while (n != 0)

{

m = (10 * m) + (n % 10);

n = n / 10;

}

Output:-

987654321

Explaination:-

• This question is very easy, the code is exactly similar to reversing of the number.
• Each iteration, m is getting multiplied with 10 and the last digit of n is getting added to m and finally, the last digit gets removed when the control executes n=n/10