Question

what is the value of m if the roots of x²+mx+m=0 are real and equal​

Answer 1

The quadratic equation has two equal and real roots.

Solution: Discriminant is zero.

Discriminant of the equation is m²-4m=0.

Then two factors are m and m-4, therefore two values of m are 0, 4.

Answer 2

Step-by-step explanation:

Consider the equation x

2

+mx+4=0

This is in the form ax

2

+bx+c=0. The co-efficients are a=1,b=m,c=4

△=b

2

−4ac,△=m

2

−4(1)(4),△=m

2

−16

If roots are equal, then △=0

∴m

2

−16=0,m

2

=16,m=±

16

∴m=4