Question

What is the value of magnetic momentum quantum number for 23rd electron of Cupric ion​

Answer 1

29

​  

Cu=2,8,18,1

=1s  

2

,2s  

2

2p  

6

,3s  

2

,3p  

6

,3d  

10

,4s  

1

 

∴ Quantum numbers for 4s  

1

 electron are:

n=4,l=0,m=0,s=+  

2

1

​  

.

Answer 2

Answer: The possible values of the magnetic momentum quantum number for the 23rd electron of the Cupric ion are -2, -1, 0, 1, and 2.

Explanation:

To determine the magnetic momentum quantum number for the 23rd electron of the Cupric ion, we need to know the electron configuration of the ion.

The Cupric ion has a +2 charge, indicating that it has lost two electrons from the neutral Copper atom. The electron configuration of the neutral Copper atom is [Ar] 3d^10 4s^1. Since two electrons are lost from the outer shell, the electron configuration of the Cupric ion is [Ar] 3d^9.

The 23rd electron corresponds to the ninth electron in the 3d subshell. The possible values of the magnetic momentum quantum number for this electron can be determined using the formula:

M_l = -l, -(l-1), ..., 0, ..., (l-1), l

where l is the azimuthal quantum number, which is determined by the type of subshell (s, p, d, f). Since we are dealing with the 3d subshell, l = 2.

Substituting l = 2 into the formula, we get:

M_l = -2, -1, 0, 1, 2

Therefore, the possible values of the magnetic momentum quantum number for the 23rd electron of the Cupric ion are -2, -1, 0, 1, and 2.

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