Question

What is the value of magnification produced by a convex lens when an object is
kept at a distance from the pole which is twice the focal length of the lens?​

Answer 1

Answer:

1/3

Explanation:

Object distance, u=−2f

Image distance, v=?

From mirror formula,

Remaining answer in attachment

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Answer 2

Answer:

The value of magnification produced by a convex lens=$\frac{1}{3}$

Explanation:

Object distance, u= −2f

Image distance, v=?

From mirror formula,

$\frac{1}{v} +\frac{1}{u}= \frac{1}{f} \\\\Here\\u=-2f$

$\frac{1}{v} +\frac{1}{-2f}= \frac{1}{f} \\\\\frac{1}{v}=\frac{1}{2f}+\frac{1}{f} \\\\v=\frac{2f}{3}$

Now,

Magnification

$M=\frac{-v}{u} \\​$

$M=\frac{-\frac{2f}{3} }{-2f}$

$M=\frac{1}{3}$

The value of magnification produced by a convex lens=$\frac{1}{3}$

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