Question

what is the value of maximum horizontal range of a projectile fixed with a velocity U​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

$max.range = \frac{ {u}^{2} }{g}$

Explanation:

Range,R is given by,

$r = \frac{ {u}^{2} sin2x}{g}$

to get max range, sin2x should be maximum.(maximum value of sin is 1)i.e,

• sin2x=1

therefore,

$max.range = \frac{ {u}^{2} \times 1}{g} \\ = \: \: \: \frac{ {u}^{2} }{g}$