Question

what is the value of minimum force acting between two charges at placed at 1m apart from each other

options:
a)ke²/2. b)ke. c)ke²/4. d)ke/2​

Answer 1

Answer:

its ke^2

Explanation:

f=k q1 q2/r^2

=k*e*e/1^2

=ke^2

Answer 2

Given:

Two charges at placed at 1m apart from each other.

To find:

Minimum force between the charges ?

Options:

a)ke²/2. b)ke² c)ke²/4 d)ke/2

Calculation:

• As per Coulomb's Law, the force between the charges is directly proportional to product of charges and inversely proportional to the square of distance of separation.

• Let's assume the charges to be 'e'.

$F = \dfrac{k \times e \times e}{ {d}^{2} }$

• 'k' is Coulomb's Constant.

$\implies F = \dfrac{k {e}^{2} }{ {1}^{2} }$

$\implies F = k {e}^{2}$

So,force is ke² (option b)