What is the value of moment of inertia of disk?
Answers
Answer:
Describe the Moment of Inertia of a Disc. Ans: Presuming that the moment of inertia of a disc about an axis which is perpendicular to it and through its center to be known it is mr2/2, where m is defined as the mass of the disc, and r is the radius of the disc.
Answer:
Moment of inertia of disc about an axis passing through center and perpendicular to plane is 1/2(M×R^2) where M is mass of disc and R is radius. ( Derivation are available in books for 11th NCERT book and 12th state boards, as well as different CET and competitive exam books)
MI(moment of inertia) about axis passing through tangent and perpendicular to plane is (3/2) MR^2 (using principle of parallel axes)
MI about axis passing through diameter in plane of disc is (1/4) MR^2 (using principle of perpendicular axes)
MI about axis passing through tangent, in plane of disc is (5/4) MR^2 (using principle of parallel axes).
Explanation:
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