Question

What is the value of n in:
2^(n-1) + 2^(n+1) = 320

Answer 1

Answer:

7

Step-by-step explanation:

2^(n-1)+2^(n+1)=320

⇒2 ^n(2^-1 +2^+1 )= 320

⇒ 2^n ( 1/2 + 2) = 320

⇒2 ^n( 5/2) = 320

⇒2^n = 320×2/5

⇒2^n=64×2

⇒2^n=128

⇒2^n=2^7

⇒thus, n = 7