Question

what is the value of 'n' solve it ​

Answer 1

Option A is perfect right answer.

Pls mark as brainliest answer

Answer 2

Answer:

(A) -1

Step-by-step explanation:

$\frac{2^{-n}\times8^{3n+1}\times16^{2n}}{4^{3n}} = \frac{1}{128}$

$or, \frac{2^{-n}\times2^{3(3n+1)}\times2^{4\times2n}}{2^{2\times3n}} = \frac{1}{2^7}$

$or,{2^{-n}\times2^{9n+3}\times2^{8n}}\times{2^{-6n}} = 2^{-7}$

$or,{2^{-n+9n+3+8n-6n} = 2^{-7}$

or, -n+9n+3+8n-6n = -7

or, 10n = -10

or, n = -1