Question

what is the value of n when np2 =12?​

Answer 1

The value of n is 3.

Step-by-step explanation:

Given: $np^2 = 12$

• That means 12 is a product of a number 'n' and a perfect square of 'p'.
• To solve this question, we can find factors of 12.
• The factors of 12 are 2, 2, 3.
• We can write 12 as $3\times 2^2$
• So, that $np^2 = 12$
• $np^2 = 3\times 2^2$

Hence, on the comparison we find, the value of n = 3 and p =2.

Answer 2

The value of n = 4

Given :

$\displaystyle \sf{ {}^{n} P_2 = 12 }$

To find :

The value of n

Solution :

Step 1 of 2 :

Write down the given equation

Here it is given that

$\displaystyle \sf{ {}^{n} P_2 = 12 }$

Step 2 of 2 :

Find the value of n

$\displaystyle \sf{ {}^{n} P_2 = 12 }$

$\displaystyle \sf{ \implies {}^{n} P_2 = 4 \times 3 }$

$\displaystyle \sf{ \implies {}^{n} P_2 = \frac{4 \times 3 \times 2}{2} }$

$\displaystyle \sf{ \implies {}^{n} P_2 = \frac{4 !}{2!} }$

$\displaystyle \sf{ \implies {}^{n} P_2 = {}^{4} P_2 }$

Comparing both sides we get n = 4

Hence the required value of n = 4

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