Question

what is the value of (omega +1)^97​

Answer 1

Answer:

1

What is the value of 1+w+w^2?

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Subhasish Debroy

Answered November 17, 2017

We know w( omega)= (1)^1/3 (w = cube root of 1)

( Practically sign of omega is different than that of w)

Taking cube on both side,

w^3 ={(1)^1/3}^3=1,

or, w^3 - 1 =0

or, w^3 - 1^3 =0

or, (w - 1)(w^2 +w +1) =0 ,

Then either w-1 =0 ,or, 1+w+w^2 =0,

As w ≠1, Therefore w-1 ≠0, Therefore

1+w+w^2 = 0