Question

What is the value of orbital velocity of the body revolving around the earth in a fixed on but thater height 1/4 times of its radius where radius of earth 6400km/h mass of earth 6x1024.​

Answer 1

Answer:

Here, h=1000 km=1000×103m=106m

r=R+h=6.38×106+106=7.38×106m

Orbital speed,

v0=R+hGM=7.38×1066.67×10−11×6×1024=7364m s−1

Time period,

T=v02πr=7.364×1032×(22/7)×(7.38×106)=6297s.