Question

what is the value of p(0) for the polynomial p(x)=(x-1)(x+1)​

Answer 1

X-1=0

X=1

X+1=0

x=-1

(1)(-1)

-1

Answer 2

Answer:

p(x)=(x-1)(x+1)

p(0)=(x2+x-x-1)

0=(x2-1)

x2=1

x=1