Question

what is the value of P(-1) for p(Y)= y^5 - Y^2 + Y?​

Answer 1

Put y=-1

(-1)^5-(-1)^2+(-1)

$- 1 - 1 - 1 \\ = - 3$

Answer 2

Answer:

the value of p(-1) is -3.

Step-by-step explanation:

p(y)= y^5-y²+y

p(-1)= (-1)^5-(-1)²+(-1)

     = -1 - 1 -1

     = -3

Hence, the value of p(-1) is -3.

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