Math, asked by sunshine25, 1 year ago

what is the value of p for which the polynomial x^3+4x^2-px-6 is completely divisible by (x-1)

Answers

Answered by Anonymous
2
P(x)=x^3+4x^2-px-6=0
p(1)=(1)^3+4(1)^2-p(1)-6.=0
p(1)=1+4-p-6=0
p(1)=5-6-p=0
p(1)=-1-p=0
-p=1
p=-1.
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