what is the value of p for which the polynomial x^3+4x^2-px-6 is completely divisible by (x-1)
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DEAR FRIEND,
LET P(X)=X^3+4X^2-PX-6 ,G(X)=X-1
ATQ,
X-1=0 {SINCE G(X) IS A FACTOR OF P(X)}
THEREFORE X=1
SO,P(X)=1^3+4*1^2-P*1-6
=1+4-P-6
=5-6-P
=-1-P
THIS IS THE ANSWER HOPE THIS WILL HELP YOU AND SORRY IF I AM WRONG :)
LET P(X)=X^3+4X^2-PX-6 ,G(X)=X-1
ATQ,
X-1=0 {SINCE G(X) IS A FACTOR OF P(X)}
THEREFORE X=1
SO,P(X)=1^3+4*1^2-P*1-6
=1+4-P-6
=5-6-P
=-1-P
THIS IS THE ANSWER HOPE THIS WILL HELP YOU AND SORRY IF I AM WRONG :)
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