what is the value of P when 47P205
in divisible by 3?
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Answer:
0 or 3 or 6 or 9
Step-by-step explanation:
For a number to be divisible by 3, the sum of its digits has to be divisible by 3
Sum of digits = 4 + 7 + P + 2 + 0 + 5 = P + 18
18 is already divisible by 3, so if P + 18 has to be divisible by 3, P has to be divisible by 3.
Therefore, P can be either 0 or 3 or 6 or 9
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