Question

What is the value of p(x) =
${x}^{2} - 3x - 4 \: at \: x = - 1$
​

Answer 1

$p(x) = {x}^{2} - 3x - 4$

$x = - 1$

$p( - 1) = {( - 1)}^{2} - 3 \times ( - 1) - 4$

$p( - 1) = 1 + 3 - 4$

$p( - 1) = 0$