Question

what is the value of p(x)=x^2-3x-4 at x =1 and 2?​

Answer 1

Answer

-6

Step-by-step explanation:

When x = 1

1-3-4= - 6

When x= 2

4-6-4= - 6

Answer 2

${\huge{\underline{\sf{\boxed{\red{Given:}}}}}}$

Find x :

$p(x) = {x}^{2} - 3x - 4$

x = 1

x = 2

______________________

${\huge{\underline{\sf{\boxed{\purple{Solution:}}}}}}$

If x is 1 :

$p(1) = {1}^{2} - 3 \times 1 - 4$

$p(1) = - 2 \times 1 - 4$

$p(x) = - 2 - 4$

${\underline{\sf{\boxed{\orange{so \: 1 \: is \: nt \: the \: 0 \: of \: ths \: eqn.}}}}}$

If x is 2 :

$p(2) = {2}^{2} - 3 \times 2 - 4$

$p(2) = 4 - 3 \times 2 - 4$

$1 \times (- 2)$

${\underline{\sf{\boxed{\orange{so \: 2 \: is \: also \: not \: 0 \: of \: the \: eqn.}}}}}$

_______________________