Question

what is the value of polynomial x^2 + 8x + k , if -1 is the zero of the polynomial ?​

Answer 1

Hey mate! Thanks for asking your question,

Given, -1 is a zero of p(x) where

p(x) = $x^2 + 8x + k$


According to the question,

p(-1) = 0

=> $(-1)^2 + 8(-1) + k = 0$

=> 1 - 8 + k = 0

=> k = 7


Hence the value of k = 7

I hope you understand #thanks

Answer 2

Answer:

Step-by-step explanation:

$\textsf{We need to Find the value of}$ x^2+8x +k

$\textsf{Where -1 is the zero of Polynomial}$

$\huge\textbf{Steps to do this Question is}$

$\textsf{1.Place -1 in place of x}$

$\textsf{2. Now this Equation will be equal to zero.}$

$\textbf{3. Find K. }$

$\textsf{Following these steps , I will solve the question.}$

(-1)^2+8(-1)+k =0  

-2 -8+k = 0

k = 10

So we have got k as 10.

Things to Remember

• Whenever a number goes towards the other side its sign changes to inverse
• Always remember the basic Formula
• x^2 - (alpha+beta)x+(alpha*beta)
• Where alpha and beta are the zeroes of Polynomial
• To find zeroes we can use Middle Term split method to find the zero.