What is the value of PV for 11.2 litre of an ideal gas at STP ?- (a) 2RT (b) RT (c) 0.5 RT (d) 11.2 RT
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Given:
Volume of gas = 11.2 litres at STP.
We know that:
1 mole of any gas at STP has a volume of 22.4 litres.
PV = nRT (Where, P is pressure, V is volume, n is no. of moles, R is gas constant, T is temperature)
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=> 11.2 liters of gas at STP is 11.2/22.4 =>1/2 => 0.5 moles
PV = 0.5 x R x T
PV = 0.5RT
Hence, the correct answer is (c) 0.5RT .
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