Math, asked by mrajendrap42, 1 month ago

What is the value of Range of these altitudes A) 12.8 B) 32 C)​

Answers

Answered by btsarmyforever90
1

Answer:

a)2³+5²

b)36²

Hope it helps uh

Answered by pruthaasl
0

Answer:

The range of the given altitudes is A) 12.8m.

Step-by-step explanation:

Given:

The measurements of the sides of a garden that is in the shape of a Scalene triangle are 40m, 32m, and 24m. The gardener wants to decorate one of the kinds of concurrent lines, namely the altitudes of the triangle with a  green ribbon.

To find:

Value of the range of altitudes.

Solution:

We know that the semi perimeter of a triangle is given as

s = (a + b + c)/2

s = (40 + 32 + 24)/2

s = 96/2

s = 48m

So, the area of the triangle is

A = √[s×(s - a)×(s - b)×(s - c)]

A = √[48×8×16×24]

A = √(8×6×8×16×4×6)

A = √(8²×8²×6²)

A = 8×8×6

A = 384 m².

Now, we know that the area of a triangle is half of the product of its base and height. Therefore,

A = (1/2) × Base × Altitude

384 = (1/2) × Base × Altitude

Therefore,

Altitude on side 40 m is

(1/2)×40×Altitude = 384

Altitude = 384×2 / 40

Altitude = 19.2 m

Altitude on side 32 m is

(1/2)×32×Altitude = 384

Altitude = 384×2 / 32

Altitude = 24 m

Altitude on side 24 m is

(1/2)×24×Altitude = 384

Altitude = 384×2 / 24

Altitude = 32 m

Range = Highest value - Lowest value

Range = 32 - 19.2

Range = 12.8 m

Therefore, the value of range is 12.8m

#SPJ3

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