What is the value of Range of these altitudes A) 12.8 B) 32 C)
Answers
Answer:
a)2³+5²
b)36²
Hope it helps uh
Answer:
The range of the given altitudes is A) 12.8m.
Step-by-step explanation:
Given:
The measurements of the sides of a garden that is in the shape of a Scalene triangle are 40m, 32m, and 24m. The gardener wants to decorate one of the kinds of concurrent lines, namely the altitudes of the triangle with a green ribbon.
To find:
Value of the range of altitudes.
Solution:
We know that the semi perimeter of a triangle is given as
s = (a + b + c)/2
s = (40 + 32 + 24)/2
s = 96/2
s = 48m
So, the area of the triangle is
A = √[s×(s - a)×(s - b)×(s - c)]
A = √[48×8×16×24]
A = √(8×6×8×16×4×6)
A = √(8²×8²×6²)
A = 8×8×6
A = 384 m².
Now, we know that the area of a triangle is half of the product of its base and height. Therefore,
A = (1/2) × Base × Altitude
384 = (1/2) × Base × Altitude
Therefore,
Altitude on side 40 m is
(1/2)×40×Altitude = 384
Altitude = 384×2 / 40
Altitude = 19.2 m
Altitude on side 32 m is
(1/2)×32×Altitude = 384
Altitude = 384×2 / 32
Altitude = 24 m
Altitude on side 24 m is
(1/2)×24×Altitude = 384
Altitude = 384×2 / 24
Altitude = 32 m
Range = Highest value - Lowest value
Range = 32 - 19.2
Range = 12.8 m
Therefore, the value of range is 12.8m
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