Question

what is the value of sec^2t+tant^2t=​

Answer 1

Answer:

sec^2t+tant^2t= 1+2tan²t

Step-by-step explanation:

sec ²t+tan²t = (1+tan²t) + tan²t

= 1+2tan²t

Answer 2

Step-by-step explanation:

${ \sec}^{2} t + { \tan }^{2} t \\ = { \sec }^{2}t + { \sec}^{2}t - 1 \\ = 2 { \sec }^{2} t - 1$

or

${ \sec}^{2} t + { \tan }^{2} t \\ = 1 + { \tan }^{2}t + { \tan}^{2}t \\ = 2 { \tan}^{2} t + 1$