Question

what is the value of sec(90-θ) .sinθ sec 45?

Answer 1

Answer:

$\sqrt{2} \sin {}^{2} ( \alpha )$

Step-by-step explanation:

$\sec(45) = \sqrt{2}$

$\sec(90 - \alpha ) = \sin {}^{2} ( \alpha )$

product of all these is the answer