what is the value of shunt resistance that
allows 20% of the mais current through
galvanameter of gg
a
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24.75 ohms.
One way to handle parallel circuits is to convert to conductance.
The conductance of the galvanometer of 99 ohms is 1/99 = 0.010101
The conductance of the added resistor needs to be 4 times the galvanometer to have 20% go through the galvanometer.
Added resistor conductance is 4 * 0.0101010 = 0.040404
1/ 0.040404 = 24.75 ohms
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