What is the value of side AB, in a right angled triangle of side AC 12.5 cm and BC = 7.5 cm.
Answers
Answered by
4
Answer:
10 c.m.
Step-by-step explanation:
considering Triangle as ABC where m<ABC = 90°
then AB = √(AC² - BC²)
= √((12.5²) - (7.5²))
=√(156.25-56.25)
= √100
= 10
Similar questions