What is the value of sin 15 degrees
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Sin15° = sin ( 45° - 30° )
= sin 45°. Cos30° - cos45°. sin30° --- (∵ Sin(A - B) = SinA.CosB - CosA.SinB)
= (1/√2) × (√3/2) - (1/√2) × (1/2)
= (√3/2√2) - (1/2√2)
= (√3 - 1)/(2√2)
∴ Sin 15° = (√3 - 1)/(2√2)
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