Question

what is the value of sin^2 48 + sin^2 42 - sec^2 30 + tan^2 60​

Answer 1

Answer:

=sin^2 48 + sin^2(90-48)-(2/√3)^2+(√3)^2

=sin^2 48 +cos^2 48 -4/3 +3

=1-4/3+3

=4-4/3=8/3 Ans