What is the value of ( sin 30 + cos 30 ) - ( sin 60 + cos 60 )
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( sin 30 + cos 30 ) - ( sin 60 + cos 60 )
( 1/2+√3/2)-(√3/2+1/2)
(1+√3/2)-(√3+1/2)
0
( 1/2+√3/2)-(√3/2+1/2)
(1+√3/2)-(√3+1/2)
0
Answered by
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sin 30= 1/2. cos30= √3/2. sin60= √3/2. cos60= 1/2
(1/2+√3/2)- (√3/2-1/2)
1+√3/2 - √3-1/2.(( divide 2 with the whole of numerator ))
(1+√3)- (√3-1)/2
1+√3-√3+1/2
both √3 s are cancelled
1+1/2
2/2
=1
(1/2+√3/2)- (√3/2-1/2)
1+√3/2 - √3-1/2.(( divide 2 with the whole of numerator ))
(1+√3)- (√3-1)/2
1+√3-√3+1/2
both √3 s are cancelled
1+1/2
2/2
=1
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