Question

what is the value of sin 45 degrees​

Answer 1

Solution:-

Consider ∆ABC to be right-angled in B and choose ∠BCA such that its measure is 45°.

Since the triangle is isosceles, we can deduce that angle ∠CAB is also 45° Then pick pick a discretionary incentive for AB and BC and apply the Pythagorean theorem. We will go with the unit triangle,choosing both AB and BC to be 1(remember, the triangle is isosceles):

The hypothenuse AC can easily be calculated now:

$AC=\sqrt{BC^{2}+AB^{2}$

$\dashrightarrow \sqrt{1^{2}+1^{2}}$

$\dashrightarrow \sqrt{2}$

The sine is defined as the ratio between the opposed side and the hypothenuse.

Therefore,

$\implies \sf{sin}\ 45^{\circ}\dfrac{1}{\sqrt{2}}$

$\implies \dfrac{\sqrt{2}}{\:\: 2}$

In decimal form, it is roughly 0.7071067812

Figure

• (In attachment)

Answer 2

Answer:

$\frac{1}{ \sqrt{2} } \: or \: 0.7071067812$

Step-by-step explanation:

It is the correct answer.