Question

what is the value of sin^6 titha+cos^6titha

Answer 1

Solution:(instead of θ I use A)

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Given & To find:

The value of :

$sin^6 A + cos^6 A$

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(sin²A)³ + (cos²A)³


we know that,

a³ + b³ = (a + b) ( a² - ab + b²)

so,

(sin²A)³ + (cos²A)³ = (sin²A + cos²A) ((sin²A)² - (sin²A cos²A) + (cos²A)²)

=> $(1) (sin^4 A - sin^2 A cos^2A +cos^4A)$

=> $sin^4A + cos^4A - sin^2Acos^2A$

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                                 Hope it Helps !!

Answer 2

Hope this is correct