Question

What is the value of sin( npi/2)

Answer 1

Answer:

Step-by-step explanation:

1

nπ/2 will be equal to 2kπ + π/2. Thus, sin(nπ/2) will be equal to 1. If n is of the form 4k+3, nπ/2 will be equal to 2kπ + 3π/2.

Answer 2

Answer:

$sin(n\pi /2)=-1.$

Step-by-step explanation:

$sin(n\pi /2)$ can not be given a general value.

when $n$ is even, $n\pi /2$ becomes an integral multiple of $\pi$. Thus, $sin(n\pi /2)$  will be zero.

if $n$ is of the form $4k+1,$

$n\pi /2$ will be equal to $2k\pi +\pi /2.$ Thus, $sin(n\pi /2)$  will be equal to $1$.

if $n$ is of the form $4k+3,$

$n\pi /2$ will be equal to $2k\pi +3\pi /2.$ Thus, $sin(n\pi /2)$  will be equal to $-1.$