what is the value of sin15
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sin15=sin(45-30)
sin(A-B)=sinA cosB +cosA sinB
sin(45-30)=sin45 cos30+ cos45 sin30
sin(45-30)=1/√2 × √3/2 +1/√2 ×1/2
sin(45-30)=√3/2√2 × 1/2√2
sin15=√3+1/2√2
sin(A-B)=sinA cosB +cosA sinB
sin(45-30)=sin45 cos30+ cos45 sin30
sin(45-30)=1/√2 × √3/2 +1/√2 ×1/2
sin(45-30)=√3/2√2 × 1/2√2
sin15=√3+1/2√2
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Answered by
0
Answer:
Step-by-step explanation:
sin45--sin 30
1/√2--1/2
=2-√2/2√2
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