Math, asked by strqwberrgyu, 15 hours ago

what is the value of sin²30+cot²30-2cos²60/4sec²45-4sin²30​

Answers

Answered by Truelover2008
0

Answer:

cot

2

30

−2cos

2

60

4

3

sec

2

45

−4sec

2

30

=(

3

)

2

−2(

2

1

)

2

−(

4

3

)(

2

)

2

−4(

3

2

)

2

=3−

4

2

4

6

3

16

=

4

12

4

2

4

6

3

16

=(

4

12−2−6

)−

3

16

=

4

4

3

16

=1−

3

16

=

3

3

3

16

=

3

−13

Step-by-step explanation:

hope it helps u ..

Answered by arjunkrishna0077
0

Step-by-step explanation:

cscA(1+cosA)(cscA−cotA)=1

LHS:

sinA

1

[1+cosA][

sinA

1

sinA

cosA

][∵cscA=

sinA

1

,cotA=

sin

A

cos

A

]

=

sinA

A

(1+cosA)

sinA

(1−cosA)

=

sin

2

A

1−cos

2

A

[∵ cos

2

A+sin

2

A=1 sin

2

A=1−cos

2

A]

=

sin

2

A

sin

2

A

=1=RHS

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