Question

what is the value of sin²A - sin²B and how?
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Answer 1

Answer:

Hey there,

We have A+B=90°

B=90°-A

Then,

sin^2A+sin^2B

=sin^2A+sin^2(90-A)

=sin^2A+cos^2A

=. 1

Hope it help you

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Answer 2

Answer:

sin(A + B).sin(A - B)

Step-by-step explanation:

sin²A - sin²B

= sin²A - sin²A.sin²B - sin²B + sin²A.sin² B

= sin²A (1 - sin²B) - sin²B(1 - sin²A)

= (sinA.cosB)² - (cosA.sinB)²

= (sinA.cosB + cosA.sinB) (sinA.cosB - cosA.sinB)

= sin(A + B).sin(A - B)

Therefore the value of sin²A -- sin²B is sin(A + B)sin(A - B) .