Question

what is the value of sin²ø-tan²ø​

Answer 1

Step-by-step explanation:

Step-by-step explanation:

\begin{gathered} \bf\red{ \mapsto: {sin}^{2} \theta = 1 } \\ \\ \bf\purple{ \mapsto:{sin}^{2} \theta = 1 } \\ \\ \bf\orange{ \mapsto: {sin} \theta = 1} \\ \\ \bf\green{ \mapsto: {sin} \theta = sin 90 \degree} \\ \\ \bf\red{ \mapsto: \theta = 90 \degree} \\ \\ \bf\orange{ \mapsto: {cos}^{2} \theta + {tan}^{2} \theta } \\ \\ \bf\purple{ \implies: {cos}^{2} 90\degree + {tan}^{2}90 \degree } \\ \\ \bf\blue{ \implies: {0}^{2} + { \infty }^{2} } \\ \\ \bf\pink{ \implies: 0 + { \infty }^{2} }\end{gathered}

↦:sin

2

θ=1

↦:sin

2

θ=1

↦:sinθ=1

↦:sinθ=sin90°

↦:θ=90°

↦:cos

2

θ+tan

2

θ

⟹:cos

2

90°+tan

2

90°

⟹:0

2

+∞

2

⟹:0+∞

2

Answer 2

Answer:

$\huge\color{blue}\boxed{\colorbox{lightgreen}{☆Ănswer☆}} \uparrow$