What is the value of sin2x when sin x=4/5?
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sin2x=2sinxcosx
if sinx=4/5 then sin²x+cos²x=1
16/25+cos²x=1
cos²x=1-16÷25
cos²x=9÷25
cosx=3÷5
sin2x=2×4÷5×3÷5
= 24÷25
if sinx=4/5 then sin²x+cos²x=1
16/25+cos²x=1
cos²x=1-16÷25
cos²x=9÷25
cosx=3÷5
sin2x=2×4÷5×3÷5
= 24÷25
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