Question

what is the value of smallest electrostatic force in nature when the charges are placed at a distance of 1m? ​

Answer 1

Explanation:

gdgdggdggdgvdvdvevdvvdvdh

Answer 2

Explanation:

$hey ♥️</p><p>Electrostatic repulsion =F= </p><p>4πϵ </p><p>o</p><p> </p><p> </p><p>1</p><p> </p><p> </p><p>(.01) </p><p>2</p><p> </p><p>q </p><p>1</p><p> </p><p> q </p><p>2</p><p> </p><p> </p><p> </p><p> </p><p></p><p>force will be minimum when q </p><p>1</p><p> </p><p> =q </p><p>2</p><p> </p><p> = minimum unit of charge =ϵ </p><p>o</p><p> </p><p> =1.6×10 </p><p>−19</p><p> C</p><p></p><p>minimum force =2.3×10 </p><p>−24</p><p> N$