Math, asked by kvnmurty, 1 year ago

What is the value of ((square root 2 )^sqrt2) ^ sqrt2 ??

Very interesting. ...

y = ({ ({ \sqrt{2} )}^{ \sqrt{2} } })^{ \sqrt{2} }
What is the value of y?

Answers

Answered by AnviGottlieb
2
heya sir!
here's your answer!

as mentioned in the QUESTION that the value of y is (square root 2 )^sqrt2) ^ sqrt2 .

the Answer will be 2
let me explain:-
= ((square root 2 )^sqrt2) ^ sqrt2

= (sqrt2)^2½^2½
(in this step we will multiply the last two sqrt2
hence the result will be :- 2

= [ sqrt2 multipled by sqrt2 will give 2 ]

hence the next step would be,

= sqrt2^2

if we do (sq.root of 2)²
Answer will be,

= 2

hence y= 2
Hope I'm clear and understandable:)

kvnmurty: which sqrt2 is multiplied by which sqrt 2 ?? 1st one with 2nd one or 2nd one with 3rd one ?
AnviGottlieb: the powers sqrt are multiplied with each other i.e. the 2nd one to the 3rd one ^^
AnviGottlieb: i would request you sir to provide me with edit option to make it more clear ^^
kvnmurty: ok
AnviGottlieb: sir it's done now ^^ kindly check :) hope it's ok now :)
kvnmurty: ok. done.
Answered by KnowMore
22
 = (( \sqrt{2} ) {}^{ \sqrt{2} } ) {} {}^{ \sqrt{2} }

Here after multiplying the powers we get.

=(√2)^√2×√2
=(√2)^2
=2

Comment below for any doubt.
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