what is the value of t in the equation: 10t-5t^2-40=0
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Explanation:
5t^2-10t+40=0
t^2- 2t + 8 = 0
t= 4,-2
Answered by
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Explanation:
the given equation can be written as
5t² - 10t + 40 = 0
or
t² - 2t + 8 = 0
finding the D(discriminant) i.e b² - 4ac
4 - 4*1*8 = - 16
as D is negative so the roots are imaginary
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