Physics, asked by avinirekraj123, 7 months ago

what is the value of t in the equation: 10t-5t^2-40=0​

Answers

Answered by mechie88
0

Explanation:

5t^2-10t+40=0

t^2- 2t + 8 = 0

t= 4,-2

Answered by tushar8138
0

Explanation:

the given equation can be written as

5t² - 10t + 40 = 0

or

t² - 2t + 8 = 0

finding the D(discriminant) i.e b² - 4ac

4 - 4*1*8 = - 16

as D is negative so the roots are imaginary

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