What is the value of tan 0, if 0 and 20 - 45° are acute angles such that sin 0 = cos (20 - 45°)?
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Answer:
Correct option is
A
1
θ+2θ−45
∘
=90
∘
3θ=135
∘
θ=45
∘
=∠A
∠C=2θ−45
∘
=(2×45)−45
∘
=90
∘
−45
∘
=45
∘
Side opposite to equal angles are equal ∠A=∠C
So, BC=AB
So, tanθ=
AB
BC
=1
Step-by-step explanation:
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