Question

What is the value of tan 0, if 0 and 20 - 45° are acute angles such that sin 0 = cos (20 - 45°)?​

Answer 1

Answer:

sin 0 = cos (20 - 45°)

=> cos (90° - 0) = cos (20 - 45°)

=> 90° - 0 = 20 - 45°

=> 30 = 135°

=> 0 = 45°

tan 0 = tan 45° = 1

HOPE THIS HELPS...

Answer 2

Answer:

θ+2θ−45 °

=90 °

3θ=135 °

θ=45 °

=∠A

∠C=2θ−45 °

=(2×45)−45 °

=90 °

−45 °

=45 °

Side opposite to equal angles are equal ∠A=∠C

So, BC=AB

So, tanθ=

AB

BC

=1