Question

What is the value of Tan 45° - 1/√3 Sec 60°?

A) (1 - 2√3)/2 B) (√2 - √3)/√6 C) (3 - 2√3)/3 D) (1 - 2√2)/2

Answer 1

Answer:

(c) 3-2✓3/3 is right answer of this question

Answer 2

$\bf \tan(45^{ \circ} ) - \frac{1}{ \sqrt{3} } \sec(60^{ \circ}) = \frac{3 - 2 \sqrt{3} }{3}$

Option C is correct.

Given:

• A trigonometric expression.
• $\tan(45^{ \circ} ) - \frac{1}{ \sqrt{3} } \sec(60^{ \circ})$

To find:

• Find the value of trigonometric expression from the options.
• A) (1 - 2√3)/2
• B) (√2 - √3)/√6
• C) (3 - 2√3)/3
• D) (1 - 2√2)/2

Solution:

Concept/Formula to be used:

• Put the value of trigonometric ratios.
• $\tan( {45}^{ \circ} ) = 1$
• $\sec( {60}^{ \circ} ) = 2$

Step 1:

Put the values in the expression.

$\tan(45^{ \circ} ) - \frac{1}{ \sqrt{3} } \sec(60^{ \circ}) = 1 - \frac{1}{\sqrt{3} } \times 2$

Step 2:

Simplify the value.

$= 1 - \frac{2}{ \sqrt{3} }$

rationalize the denominator.

$= 1 - \frac{2}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }$

or

$= 1 - \frac{2 \sqrt{3} }{ 3 }$

or

$\frac{3 - 2 \sqrt{3} }{3}$

Thus,

$\bf \tan(45^{ \circ} ) - \frac{1}{ \sqrt{3} } \sec(60^{ \circ}) = \frac{3 - 2 \sqrt{3} }{3}$

Option C is correct.

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1) Find the value of Tan2 60°+Cot2 30°/Sin2 30°+Cos2 60°

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2) sin 60° + cot 45° - cosec 30°

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4,5-9 4.3 +9 95-4 93 +4

a.

b.

d.

33

33

...

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