Question

What is the value of (tan 5A)(tanA)? ​

Answer 1

Step-by-step explanation:

tanA + cotA = 2

tan A + 1/tan A = 2

[tan ^2 A + 1 ] / tan A = 2

tan ^2 A -2 tan A + 1 =0

(tan A -1)^2 =0

tan A - 1 =0

tan A = 1

cot A = 1

tan^5 A + cot^5 A

= 1 + 1 

= 2

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